Physics Medium 100× since 2002 Q8147 A particle executes simple harmonic motion and is located at x = a, b and c at times t₀, 2t₀ and 3t₀ respectively. The freqquency of the oscillation is :
A 1 2 π t 0 cos − 1 ( a + c 2 b ) {1 \over {2\,\pi \,{t_0}}}{\cos ^{ - 1}}\left( {{{a + c} \over {2b}}} \right) 2 π t 0 1 cos − 1 ( 2 b a + c ) B 1 2 π t 0 cos − 1 ( a + b 2 c ) {1 \over {2\,\pi \,{t_0}}}{\cos ^{ - 1}}\left( {{{a + b} \over {2c}}} \right) 2 π t 0 1 cos − 1 ( 2 c a + b ) C 1 2 π t 0 cos − 1 ( 2 a + 3 c b ) {1 \over {2\,\pi \,{t_0}}}{\cos ^{ - 1}}\left( {{{2a + 3c} \over b}} \right) 2 π t 0 1 cos − 1 ( b 2 a + 3 c ) D 1 2 π t 0 cos − 1 ( a + 2 b 3 c ) {1 \over {2\,\pi \,{t_0}}}{\cos ^{ - 1}}\left( {{{a + 2b} \over {3c}}} \right) 2 π t 0 1 cos − 1 ( 3 c a + 2 b ) Check answer Skip
JEE Main 2018 · 16 Apr, Morning shift · Q8147· Simple Harmonic Motion