PhysicsEasy183×since 2002Q6041A nucleus of mass M+M+M+Δm\Delta mΔm is at rest and decays into two daughter nuclei of equal mass M2{M \over 2}2M each. Speed of light is c.c.c. The binding energy per nucleon for the parent nucleus is E1{E_1}E1 and that for the daughter nuclei is E2.{E_2}.E2. ThenAE2=2E1{E_2} = 2{E_1}E2=2E1BE1>E2{E_1} > {E_2}E1>E2CE2>E1{E_2} > {E_1}E2>E1DE1=2E2{E_1} = 2{E_2}E1=2E2Check answerSkip