MathematicsMedium128×since 2002Q5620A light ray emits from the origin making an angle 30∘^\circ∘ with the positive xxx-axis. After getting reflected by the line x+y=1x+y=1x+y=1, if this ray intersects xxx-axis at Q, then the abscissa of Q is :A2(3−1){2 \over {\left( {\sqrt 3 - 1} \right)}}(3−1)2B23−3{2 \over {3 - \sqrt 3 }}3−32C32(3+1){{\sqrt 3 } \over {2\left( {\sqrt 3 + 1} \right)}}2(3+1)3D23+3{2 \over {3 + \sqrt 3 }}3+32Check answerSkip