PhysicsMedium68×since 2002Q7544A heavy iron bar, of weight WWW is having its one end on the ground and the other on the shoulder of a person. The bar makes an angle θ\thetaθ with the horizontal. The weight experienced by the person is :AWsinθW \sin \thetaWsinθBWWWCW2\frac{W}{2}2WDWcosθW \cos \thetaWcosθCheck answerSkip