MathematicsMedium175×since 2002Q2751A function y=f(x)y=f(x)y=f(x) has a second order derivative f′′(x)=6(x−1).f''\left( x \right) = 6\left( {x - 1} \right).f′′(x)=6(x−1). If its graph passes through the point (2,1)(2, 1)(2,1) and at that point the tangent to the graph is y=3x−5y = 3x - 5y=3x−5, then the function is :A(x+1)2{\left( {x + 1} \right)^2}(x+1)2B(x−1)3{\left( {x - 1} \right)^3}(x−1)3C(x+1)3{\left( {x + 1} \right)^3}(x+1)3D(x−1)2{\left( {x - 1} \right)^2}(x−1)2Check answerSkip