PhysicsMedium70×since 2002Q8615A force F→=(5i→+3j→+2k→)N\overrightarrow F = \left( {5\overrightarrow i + 3\overrightarrow j + 2\overrightarrow k } \right)NF=(5i+3j+2k)N is applied over a particle which displaces it from its origin to the point r→=(2i→−j→)m.\overrightarrow r = \left( {2\overrightarrow i - \overrightarrow j } \right)m.r=(2i−j)m. The work done on the particle in joules isA+10+10+10B+7+7+7C−7-7−7D+13+13+13Check answerSkip