PhysicsMedium49×since 2002Q8078A circular disc XXX of radius RRR is made from an iron plate of thickness t,t,t, and another disc YYY of radius 444 RRR is made from an iron plate of thickness t4.{t \over 4}.4t. Then the relation between the moment of inertia IX{I_X}IX and IY{I_Y}IY isAIY=32IX{I_Y} = 32{I_X}IY=32IXBIY=16IX{I_Y} = 16{I_X}IY=16IXCIY=IX{I_Y} = {I_X}IY=IXDIY=64IX{I_Y} = 64{I_X}IY=64IXCheck answerSkip