PhysicsMedium94×since 2002Q5921A capacitor of capacitance 150.0 μF150.0 ~\mu \mathrm{F}150.0 μF is connected to an alternating source of emf given by E=36sin(120πt)V\mathrm{E}=36 \sin (120 \pi \mathrm{t}) \mathrm{V}E=36sin(120πt)V. The maximum value of current in the circuit is approximately equal to :A12A\frac{1}{\sqrt{2}} A21AB22A2 \sqrt{2} A22AC2A\sqrt{2} A2AD2A2 A2ACheck answerSkip