PhysicsMedium159×since 2002Q7238A body is released from a height equal to the radius (R)(\mathrm{R})(R) of the earth. The velocity of the body when it strikes the surface of the earth will be (Given g=g=g= acceleration due to gravity on the earth.)AgR2\sqrt{\frac{g R}{2}}2gRB4gR\sqrt{4 g R}4gRC2gR\sqrt{2 g R}2gRDgR\sqrt{g R}gRCheck answerSkip