PhysicsMedium65×since 2002Q7867A ball is thrown up vertically with a certain velocity so that, it reaches a maximum height h. Find the ratio of the times in which it is at height h3\frac{h}{3}3h while going up and coming down respectively.A2−12+1\frac{\sqrt{2}-1}{\sqrt{2}+1}2+12−1B3−23+2\frac{\sqrt{3}-\sqrt{2}}{\sqrt{3}+\sqrt{2}}3+23−2C3−13+1\frac{\sqrt{3}-1}{\sqrt{3}+1}3+13−1D13\frac{1}{3}31Check answerSkip