PhysicsMedium53×since 2003Q7794A ball is projected from the ground with a speed 15 ms^−-−1 at an angle θ\thetaθ with horizontal so that its range and maximum height are equal, then 'tan θ\thetaθ' will be equal to :A14{1 \over 4}41B12{1 \over 2}21C2D4Check answerSkip