0.27 g of a long chain fatty acid was dissolved
in 100 cm³ of hexane. 10 mL of this solution
was added dropwise to the surface of water in
a round watch glass. Hexane evaporates and a
monolayer is formed. The distance from edge
to centre of the watch glass is 10 cm. What is
the height of the monolayer?
[Density of fatty acid = 0.9 g cm^–3, = 3]