01Easy66×since 2002Q4080Considering only the principal values of inverse trigonometric functions, the number of positive real values of xxx satisfying tan−1(x)+tan−1(2x)=π4\tan ^{-1}(x)+\tan ^{-1}(2 x)=\frac{\pi}{4}tan−1(x)+tan−1(2x)=4π is :Amore than 2B2C0D1Check answerSkip
02Easy66×since 2002Q4081If a=sin−1(sin(5))a=\sin ^{-1}(\sin (5))a=sin−1(sin(5)) and b=cos−1(cos(5))b=\cos ^{-1}(\cos (5))b=cos−1(cos(5)), then a2+b2a^2+b^2a2+b2 is equal toA25B4π2+254 \pi^2+254π2+25C8π2−40π+508 \pi^2-40 \pi+508π2−40π+50D4π2−20π+504 \pi^2-20 \pi+504π2−20π+50Check answerSkip
03Medium66×since 2002Q4082Given that the inverse trigonometric function assumes principal values only. Let x,yx, yx,y be any two real numbers in [−1,1][-1,1][−1,1] such that cos−1x−sin−1y=α,−π2≤α≤π\cos ^{-1} x-\sin ^{-1} y=\alpha, \frac{-\pi}{2} \leq \alpha \leq \picos−1x−sin−1y=α,2−π≤α≤π. Then, the minimum value of x2+y2+2xysinαx^2+y^2+2 x y \sin \alphax2+y2+2xysinα isA0B−-−1C12\frac{1}{2}21D−12\frac{-1}{2}2−1Check answerSkip
04Hard66×since 2002Q4083cot−1(cosα)−tan−1(cosα)=x,{\cot ^{ - 1}}\left( {\sqrt {\cos \alpha } } \right) - {\tan ^{ - 1}}\left( {\sqrt {\cos \alpha } } \right) = x,cot−1(cosα)−tan−1(cosα)=x, then sin x is equal to :Atan2(α2){\tan ^2}\left( {{\alpha \over 2}} \right)tan2(2α)Bcot2(α2){\cot ^2}\left( {{\alpha \over 2}} \right)cot2(2α)Ctanα\tan \alphatanαDcot(α2)cot\left( {{\alpha \over 2}} \right)cot(2α)Check answerSkip
05Medium66×since 2002Q4084If cos−1x−cos−1y2=α,{\cos ^{ - 1}}x - {\cos ^{ - 1}}{y \over 2} = \alpha ,cos−1x−cos−12y=α, then 4x2−4xycosα+y24{x^2} - 4xy\cos \alpha + {y^2}4x2−4xycosα+y2 is equal to :A2sin2α2\sin 2\alpha2sin2αB444C4sin2α4{\sin ^2}\alpha4sin2αD−4sin2α-4{\sin ^2}\alpha−4sin2αCheck answerSkip
06Medium66×since 2002Q4085If sin⁻¹(x5)\left( {{x \over 5}} \right)(5x) + cosec⁻¹(54)\left( {{5 \over 4}} \right)(45) = π2{\pi \over 2}2π, then the value of x is :A4B5C1D3Check answerSkip
07Easy66×since 2002Q4086The value of cot(cosec−153+tan−123)cot\left( {\cos e{c^{ - 1}}{5 \over 3} + {{\tan }^{ - 1}}{2 \over 3}} \right)cot(cosec−135+tan−132) is :A617{{6 \over 17}}176B317{{3 \over 17}}173C417{{4 \over 17}}174D517{{5 \over 17}}175Check answerSkip
08Medium66×since 2002Q4087If x,y,zx, y, zx,y,z are in A.P. and tan−1x,tan−1y{\tan ^{ - 1}}x,{\tan ^{ - 1}}ytan−1x,tan−1y and tan−1z{\tan ^{ - 1}}ztan−1z are also in A.P., then :Ax=y=zx=y=zx=y=zB2x=3y=6z2x=3y=6z2x=3y=6zC6x=3y=2z6x=3y=2z6x=3y=2zD6x=4y=3z6x=4y=3z6x=4y=3zCheck answerSkip
09Medium66×since 2002Q4088Let tan−1y=tan−1x+tan−1(2x1−x2),{\tan ^{ - 1}}y = {\tan ^{ - 1}}x + {\tan ^{ - 1}}\left( {{{2x} \over {1 - {x^2}}}} \right),tan−1y=tan−1x+tan−1(1−x22x), where ∣x∣<13.\left| x \right| < {1 \over {\sqrt 3 }}.∣x∣<31. Then a value of yyy is :A3x−x31+3x2{{3x - {x^3}} \over {1 + 3{x^2}}}1+3x23x−x3B3x+x31+3x2{{3x + {x^3}} \over {1 + 3{x^2}}}1+3x23x+x3C3x−x31−3x2{{3x - {x^3}} \over {1 - 3{x^2}}}1−3x23x−x3D3x+x31−3x2{{3x + {x^3}} \over {1 - 3{x^2}}}1−3x23x+x3Check answerSkip
10Medium66×since 2002Q4089The value of tan⁻¹ [1+x2+1−x21+x2−1−x2],\left[ {{{\sqrt {1 + {x^2}} + \sqrt {1 - {x^2}} } \over {\sqrt {1 + {x^2}} - \sqrt {1 - {x^2}} }}} \right],[1+x2−1−x21+x2+1−x2], ∣x∣<12,x≠0,\left| x \right| < {1 \over 2},x \ne 0,∣x∣<21,x=0, is equal to :Aπ4+12cos−1 x2{\pi \over 4} + {1 \over 2}{\cos ^{ - 1}}\,{x^2}4π+21cos−1x2Bπ4+cos−1 x2{\pi \over 4} + {\cos ^{ - 1}}\,{x^2}4π+cos−1x2Cπ4−12cos−1 x2{\pi \over 4} - {1 \over 2}{\cos ^{ - 1}}\,{x^2}4π−21cos−1x2Dπ4−cos−1 x2{\pi \over 4} - {\cos ^{ - 1}}\,{x^2}4π−cos−1x2Check answerSkip